Did you solve it? Naughty noughts and crosses | Mathematics

Earlier today I set you a puzzle about a variant of noughts and crosses (tic-tac-toe in the US). Games are played exactly as normal with the following twist:

Players can place either an X or an O on each go.

That’s right, you can swing both ways. A player can play X on one go and O on the next, or vice versa, or stick with the same symbol. On each go, it is up to the player to decide. As per usual, the first player to get a line of three Os or Xs wins.

Today’s puzzle asked: if you go first, how do you always guarantee a win?

Before you scroll to the solution, you might want to check out the original post, which had an example game.

Solution

Player 1 (red) goes first in the middle with, say X. This forces player 2 to place an O, as an X placed anywhere will let player 1 win.

Scenario 1: Player 2 places an O in the corner

For their second move, player 1 places a O in the opposite corner. This move forces a win since player 2 cannot place an O or an X anywhere.

Scenario 2: Player 2 places an O on the side.

In their second move, player 2 places an O on the opposite side. For the next two moves, the only safe spaces are Os on the other two sides. This pattern also guarantees a win for player 1, since any corner in either X or O leads to a three-in-a-row.

Thanks to John Driscoll, the author of A Hen and a Half, Intriguing Conundrums, Confusing Paradoxes, Baffling Conjectures and Challenging Puzzles, where I first read about this puzzle. Readers of this column will find his book full of entertaining material.

I’ve been setting a puzzle here on alternate Mondays since 2015. I’m always on the look-out for great puzzles. If you would like to suggest one, email me.

My new book, Think Twice: Solve the simple puzzles (almost) everyone gets wrong (Square Peg, £12.99), is out on September 5. To support the Guardian and Observer, order your copy at guardianbookshop.com. Delivery charges may apply.

Read original article here

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